Jason's age is 3 times Shauna's present age. In 4 years' time, the sum of their ages will be 56 years. Find their present ages.

Question

02-05-2018
Mathematics

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Jason's age is 3 times Shauna's present age. In 4 years' time, the sum of their ages will be 56 years. Find their present ages.

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mooostache00 mooostache00 · Answer 1 · 2018-05-02T00:33:57+02:00

mooostache00 mooostache00

02-05-2018

Hello there!
J = Jason
S = Shauna
You can use the equation :
(J+4)+(S+4)=56
4s + 8 = 56
4s = 56
s = 12
J=36In 4 years Jason is 40 and Shauna is 16.
Hope this helps! :D

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