Respuesta :

sqdancefan
[tex]\log_{4}(240)=\log_{4}(3 \cdot 4^{2} \cdot 5) = \log_{4}(3) +\log_{4}(4^{2}) +\log_{4}(5) = 0.7925 +2 +1.1610 = 3.9535[/tex]

[tex]\log_{4}(240) \approx 3.9535[/tex]