Respuesta :

a.  P( first 2 are 6 and last 6 not 6) = 1/6 * 1/6 * (5/6)^6 =  0.0093027

there are 8C2 ways of getting 2  6's in 8 throws 

= 8C2 =   28

So the required probability = 28 * 0.0093027 =  0.26   to nearest hundredth.

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