04-01-2018
Mathematics

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Find the minimum point of y=5+3x-x^2
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Аноним Аноним

04-01-2018

This will be a maximum point as the coefficient of x^2 is negative.
y' = -2x + 3 = 0

x = 1.5

y = 5 + 3(1.5) - 1.5^2 = 7.25

required point is (1.5,7.25)

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