what you are asking is
[tex]4 \frac{1}{3} -2 \frac{3}{4} [/tex]
we need to make the fractions improper now,
[tex] \frac{13}{3} - \frac{11}{4} [/tex]
now we need common denominators:
[tex] \frac{52}{12} - \frac{33}{12} [/tex]
we get
[tex] \frac{19}{12} [/tex]
OR
[tex]1 \frac{7}{12} [/tex]
