How many grams of NaF form when .508 mol of HF react with excess Na2SiO3?

Question

Allie1123 Allie1123

04-09-2017
Chemistry

contestada

How many grams of NaF form when .508 mol of HF react with excess Na2SiO3?

Respuesta :

Otras preguntas

Rewards and Punishment examples

WILL GIVE BRAINLIEST IF ANSWERED FAST!!!

Add the additive inverse of 5 to the product of -1 and -4 show all

The 4th and 3rd terms. of two GoP₂ (A and B) are 36 and 54 respectively. The ratio of the first team of A to that of B is Find : (i) the value of a 2a 3a. (i) t

pqr is an isosceles triangle in which pq=pr m and n are points on pq and pr

A lot of ——— (gentle) is needed to look after a baby (suffix used)

challenges of owning a tarven

lucy starts 4miles from home and jogs away from home at 6mph for 20minutes. draw this statement on the diagram for me please.

Аноним Аноним · Answer 1 · 2017-09-04T19:01:48+02:00

Аноним Аноним

04-09-2017

2HF + Na2SiO3 ----> 2NaF + H2SiO3 is the balanced equation.

2 moles of HF form 2 moles of NaF

therefore 0.508 Mol HF forms 0.508 mol of NaF

In grams this is 0.508( rel atomic mass of Na + RAM of F)
= 0.508 (22.99+19)
= 21.33 grams

Answer Link