Respuesta :

wolf1728
2x^2 + 3x + 5 = 0
a = 2 b = 3 and c = 5
x = [-b +-sq root(b^2 -4ac)] / 2a
x = [-3 +-sq root(9 -4*2*5)] / 4
x = [-3 +-sq root(9 - 40)] / 4
x = -(3 / 4) + sq root (-36) / 4
x = -(3 / 4) - sq root (-36) / 4