SOLUTION:
For parallelograms; opposite sides are congruent;
Thus;
[tex]\begin{gathered} 2y-12=y-2 \\ solving\text{ for y} \\ 2y-y=12-2 \\ y=10 \end{gathered}[/tex]
The shorter opposite sides must be equal too, thus;
[tex]\begin{gathered} 2x+1=y+3 \\ substitute\text{ in y = 10} \\ 2x+1=10+3 \\ 2x+1=13 \\ 2x=12 \\ x=6 \end{gathered}[/tex]
Thus, for the figure to be a parallelogram, x = 6 and y = 10
