Respuesta :

h(x) = x^2 + 5

h(-2) = (-2)^2 + 5 = 4 + 5 = 9

h(-1) = (-1)^2 + 5 = 1 + 5 = 6

h(0) = (0)^2 + 5 = 5

h(1) = (1)^2 + 5 = 1 + 5 = 6

h(2) = (2)^2 + 5 = 4 + 5 = 9

The range is {9, 6, 5, 6, 7]

Ver imagen BreysonH245391

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