VaileK163597 VaileK163597
  • 03-11-2022
  • Mathematics
contestada

(300/m) + 44n m=15 n=4

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JadienN175683 JadienN175683
  • 03-11-2022

Solve (300/m) + 44n where m = 15 and n = 4

[tex]\begin{gathered} (\frac{300}{m})+44n \\ \text{Substitute for the values of m and n, and you have;} \\ (\frac{300}{15})+44(4) \\ 20+176 \\ 196 \end{gathered}[/tex]

The solution to the expression is 196

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