Respuesta :

t (x) = 1/x + 3

t (x) ⇒ y

y = 1/x + 3

when x = 1

y = 1/1 + 3 = 1 + 3 = 4

y = 4(Graph 4)

t (x)= -1/x + 3

t (x) ⇒ y

y = -1/x + 3

when x = 1

y =-1/1 + 3 = - 1 + 3 = 2

y = 2(Graph 2 )

Hence, the correct graph to these equations is Graph 4 & Graph 2

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