Given:
[tex]\frac{-10+50}{-4-16}-4\cdot(-2)[/tex][tex]\frac{-10+50}{-4-16}-4\cdot(-2)=\frac{40}{-20}-4\cdot(-2)_{}[/tex][tex]\frac{-10+50}{-4-16}-4\cdot(-2)=-2-4(-2)[/tex][tex]\frac{-10+50}{-4-16}-4\cdot(-2)=-2+8[/tex][tex]\frac{-10+50}{-4-16}-4\cdot(-2)=6[/tex]
Therefore, 6 is the correct answer.
