The decay model is given as,
[tex]A\text{ = 16e}^{-0.000121t}[/tex]
After t = 9433 years,
[tex]\begin{gathered} A\text{ = 16e}^{-0.000121\times9433} \\ A\text{ = 16e}^{-1.141393} \\ A\text{ = 16 }\times\text{ 0.3194} \\ A\text{ = 5.11 }\approx\text{ 5} \end{gathered}[/tex]
Thus amount of carbon left is 5 grams.
