Since the paper is rectangular, opposite sides of the paper are congruent.
The perimeter of the paper is given by the sum of all sides, so we have:
[tex]\begin{gathered} P=2\cdot length+2\cdot width\\ \\ P=2\cdot16+2\cdot10\\ \\ P=32+20\\ \\ P=52\text{ inches} \end{gathered}[/tex]Therefore the perimeter of the paper is 52 inches.
