The figure is a right-angled triangle so we can use trigonometric ratios to solve for E.
Side DE is adjacent to That is
[tex]\begin{gathered} \cos E=\frac{5}{5.83} \\ \text{this implies that} \\ E=\cos ^{-1}(\frac{5}{5.83})=31^0 \end{gathered}[/tex]
Since [tex]\begin{gathered}
