disance between (x1,y1) and (x2,y2) is [tex]D= \sqrt{(x2-x1)^2+(y2-y1)^2} [/tex] given (-2,5) (3,-4) [tex]D= \sqrt{(3-(-2))^2+(-4-5)^2} [/tex] [tex]D= \sqrt{(5)^2+(-9)^2} [/tex] [tex]D= \sqrt{25+81} [/tex] D=√106 the distance is √106 units or abotu 10.2
