Respuesta :

shimanekgare

Answer:

7.00335g

Explanation:

[tex]n=\frac{V}{V_m} \\n = \frac{11.2}{22.4} \\n= 0.5 mol[/tex]

[tex]n=\frac{m}{M} \\m=nM\\m=(0.5)(14.0067)\\m=7.00335g[/tex]