Answer:
D. x = 15
Step-by-step explanation:
an equation can be formed to solve this if has same sides but enlarged:
[tex]\frac{x-6}{x-6+3} = \frac{x}{x+5}[/tex]
(x-6)(x+5) = (x)(x-3)
x²+5x-6x-30=x²-3x
x² - x² -x +3x = 30
2x = 30
x = 30/2
x = 15
