Step-by-step explanation:
Given,
∠CBE ≅ ∠DBE ----> 1
∠CBE ≅ ∠BCA ----> 2
From 1 & 2,
∠BCA≅ ∠DBE ----> 3
∠DBE ≅ ∠BAC ----> 4
Reason,
Since BE II AC, corresponding angles are equal.
From 3 & 4,
∠BCA ≅ ∠BAC
BC is opposite to ∠BCA
AB is opposite to ∠ABC
Side opposite to congruent angles are always congruent.
Therefore,
AB ≅ BC
Hence proved.
