Respuesta :

caylus

Answer:

Hello,

We don't need vw(x) !

[tex]w^{-1}(x)=\dfrac{x-1}{2}[/tex]

Step-by-step explanation:

[tex]w(x)=2x+1=y\\\\2y+1=x \ exchanging \ x\ and\ y\\\\y=\dfrac{x-1}{2} \\\\w^{-1}(x)=\dfrac{x-1}{2}[/tex]

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