Respuesta :

MohamedSharif
a^2+6a+9/a-10(put everything over 1 except 9\a
a^2\1+6a\1+9\a-10\1(multiply a by everything on the numerator and everything on the denominator by 1
a*a^2\a*1+a*6a\a*1+9\a-a*10\a*1
=a^3\a+6a^2\a+9\a-10a\a
answer=a^3+6a^2+9-10a everything over a

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