Answer:
[tex]\frac{3x+4y^2}{3x+y^3}[/tex]
Step-by-step explanation:
Given
[tex]\frac{6x^3+8x^2y^2}{6x^3+2x^2y^3}[/tex] ← factor numerator/ denominator
= [tex]\frac{2x^2(3x+4y^2)}{2x^2(3x+y^3)}[/tex] ← cancel 2x² on numerator/ denominator
= [tex]\frac{3x+4y^2}{3x+y^3}[/tex]
