Answer:
[tex]cscx=\frac{1}{sinx}\\\\\2=\frac{1}{sinx} \\\\sinx=\frac{1}{2}>0\\\\Quadrant\ I,\ II \\\\=> x=\frac{\pi}{6} ,\frac{5\pi}{6} \\\\but\ cosx<0,\ so\ x=\frac{5\pi}{6} \ (Quadrant\ II)[/tex]
I'm not sure what the question is but I guess it asks for theta...
