Answer:
[tex] A_{sector} \approx \: 80.38 \: {ft}^{2} [/tex]
Step-by-step explanation:
[tex] A_{sector} = \frac{ \theta}{360 \degree} \times \pi {r}^{2} \\ \\ A_{sector} = \frac{144 \degree}{360 \degree} \times 3.14 \times {(8)}^{2} \\ \\ A_{sector} = 0.4 \times 3.14 \times {(8)}^{2} \\ \\ A_{sector} = 80.384 \\ \\ A_{sector} \approx \: 80.38 \: {ft}^{2} [/tex]
