jhon2345677 jhon2345677

02-11-2016
Mathematics

contestada

solve each system by substitution x+12y=68
x=8y-12

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PhantomRealm PhantomRealm

02-11-2016

substitute x=8y-12 into first equation
8y-12+12y=68
20y=68+12
20y=80
y=80/20
y=4

substitute y=4 in 2nd equ
x=8(4)-12
x=32-12
x=20

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