9514 1404 393
Answer:
c. -6
Step-by-step explanation:
We note that f(x) in the neighborhood of x=1 is ...
f(x) = 4x-5 . . . x < 3
so f(1) = -1, f'(1) = 4.
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The derivative of the given function is ...
[tex]g'(x)=\dfrac{f(x)\cdot2x-x^2\cdot f'(x)}{f(x)^2}\\\\g'(x)=\dfrac{-1\cdot2\cdot1-1^2\cdot4}{(-1)^2}=\dfrac{-2-4}{1}\\\\\boxed{g'(x)=-6}[/tex]
