Respuesta :

Navinash

3y^-4 × (2y^-4) = 6y^-8

= 6/1/y^8

= 6/y^8

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1) When x^1 multiply with x^2, 1 will add to 2 and become 3

= x^3

2) y^-1 = 1/y

3^-2 = 1/3^2 = 1/9

5^-2 = 1/5^2 = 1/25

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