Answer: 2.2532
Step-by-step explanation:
From the table attached :
Expected probability = sum of p(x) * x ; wher P-X) is the probability of x
E(p(x), x) = (0*0) + (1 * 0.06) *(2*0.1) + (3 * 0.16) * (4 *0.16)+ (5*0.26) * (6 *0.08) + (7 * 0.13) + (8 * 0.05)
Pp(x) * x) = 2.2532
Therefore, the expected value of the distribution is 2.2532
