Answer:
[tex]14.\:\:\overline{RT}=3.3\:ft[/tex]
Step-by-step explanation:
Using the definition of similar triangle, we have the equation for problem no. 14 as:
[tex]\frac{\overline{QT}}{\overline{RT}}=\frac{\overline{RT}}{\overline{TS}}\\\\\frac{5}{x}=\frac{x}{2.2}\\\\\Rightarrow x=3.3[/tex]
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