Answer:
17.2
Step-by-step explanation:
3x=12+y
x=12+y/3
[tex]8( \frac{12 + y}{3}) \div 2y[/tex]
[tex] \frac{96 + 8y}{3} \times \frac{1}{2y} [/tex]
[tex] \frac{96 + 8y}{6y} [/tex]
(y is divided by y so it no longer exists)
[tex] \frac{96 + 8}{6} [/tex]
[tex] \frac{104}{6} [/tex]
[tex]17.2[/tex]
