Answer:
(-2, -16)
Step-by-step explanation:
the minimum is at the vertex which can be found using -b/2a for the x-value of the vertex.
y = 3x^2 + 12x - 4
= ax^2 + bx - c
b = 12, a = 3
-12/(2(3))
-12/6
x = -2
y = 3(-2)^2 + 12(-2) - 4
y = -16
(-2, -16)
