Respuesta :

dalendrk
[tex]d_1;\ d_2-the\ diagonals\ of\ the\ rhombus\\\\The\ area\ of\ the\ rhombus:A=\dfrac{d_1\cdot d_2}{2}.\\\\d_1=|AC|=8\ cm;\ d_2=|BD|=3.2\ cm\\\\A=\dfrac{8\cdot3.5}{2}=4\cdot3.5=\boxed{14\ (cm^2)}[/tex]