Respuesta :

Answer:

Step-by-step explanation:

[tex]8^{c+1}=16^{2c+3}\\(2^{3} )^{c+1} =(2^{4}) ^{2c+3} \\2^{3(c+1)} =2^{4(2c+3)} \\3(c+1)=4(2c+3)\\3c+3=8c+12\\8c-3c=3-12\\5c=-9\\c=-\frac{9}{5}[/tex]

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