Answer:
S=400m
Explanation:
Given t=10.and [tex]a=8m/s^2[/tex],
Initial velocity,[tex]u[/tex], of the car is zero.
To find distance,[tex]s[/tex]
[tex]S=ut+0.5at^2[/tex]
[tex]S=0\times10+0.5\times8\times10^2\\S=400m[/tex]
Therefore, car's position after 10seconds is 400m away from the start.
