Answer:
18.51 Ω
Explanation:
Power dissipated in electric circuits is given by P = IV
But, V = IR And I = V/R
P = (V/R) V = V²/R
But this is an AC circuit, and the voltage in the power dissipated equation is the DC voltage.
DC voltage of the AC circuit = Vrms = (Vpeak)/√2 = 72/√2 = 50.912 V
P = V²/R
R = V²/P = 50.912²/140 = 18.51 Ω
