HotaroKim
HotaroKim HotaroKim
  • 02-03-2020
  • Physics
contestada

A lightbulb consumed 1100J in 30 minutes. Find Power, resistance, and calculate energy in kWh

Respuesta :

MathPhys
MathPhys MathPhys
  • 02-03-2020

Explanation:

30 minutes is 1800 seconds.

Power = energy / time

P = 1100 J / 1800 s

P = 0.611 W

Converting the energy from J to kWh:

1100 J × (1 Ws / 1 J) × (1 kW / 1000 W) × (1 h / 3600 s) = 3.06×10⁻⁴ kWh

To find resistance, you need to be given either the voltage or the current.

Answer Link

Otras preguntas

Which decimal below is equivalent to 5/9?
Can someone help me out with this question fast!?!?!
What is a tree? I’m graduated so my points are up for grabs cause I’ll never use them. I have to at least as a question with it though.
What is the formula of Sodium Sulfide? A) Na3S₂ B) NaS₂ C) Na₂S D) Nas
Charlie took a nap. He fell asleep at 11:25 AM and he woke up at 3:12 PM. How long did he sleep?
How are you feeling today
How do you drown a blonde?
Solve the equation, 2x + 1 = 3, for x. Which of the following properties of equality did you apply? Question 5 options: A) Subtraction and division B) Subtracti
5. What metaphor did Las Casas use to describe the natives and where does this metaphor come from?
d Bula drives to work and back every day. One way, the trip is fifty miles. How many miles does she drive in five days?