Answer:
Step-by-step explanation:
when x=0
y=2 sin 0=2×0=0
when x=π/2
y=2×sin (π/2)=2×1=2
when x=π
y=2 sin π=2×0=0
when x=3π/2
y=2 sin (3π/2)=2×-1=-2
when x=2π
y=2 sin (2π)=2×1=2
[tex]if ~0\leq x\leq 2\pi \\initial ~point~is ~(0,2)\\end~point~is ~(2\pi ,0)[/tex]
