Respuesta :

toporc
The nth term of an arithmetic sequence is found from:
[tex]n_{th}\ term=a+(n-1)d[/tex]
Plugging in the given values, we get for the 13th term:
-58=14+12d
12d =-58 - 14 = -72
d = -6
So, the 32nd term is:
[tex]a_{32}=14+(32-1)-6=-172[/tex]