Answer:
MgBr2(aq) + 2КОH (aq)=2KBr(aq) + Mg(OH)2
Mg²⁺ + 2Br⁻ + 2K⁺ +2OH⁻ = 2K⁺ + 2Br⁻ + Mg²⁺ + 2OH⁻
Explanation:
Number of atoms must be equal in chemical reaction. Because of that, we ad number 2 in front of KOH and KBr. Both of these compaunds are electrolytes and we can write them in ionic form.
