Answer:
[tex]\large\boxed{\dfrac{65y^3+15y^2-25y}{5y}=13y^2+3y-5}[/tex]
Step-by-step explanation:
[tex]\dfrac{65y^3+15y^2-25y}{5y}=\dfrac{65y^3}{5y}+\dfrac{15y^2}{5y}-\dfrac{25y}{5y}\\\\=13y^2+3y-5[/tex]
