adipalmer adipalmer
  • 01-11-2019
  • Mathematics
contestada

Show that in a quadrilateral ABCD, AB+BC+CD+DA<2(BD+AC)

Respuesta :

Rishi2005
Rishi2005 Rishi2005
  • 01-11-2019

Step-by-step explanation:

We know that the length of the diagonals will be more than the side.

Lets suppose the quadrilateral is a rectangle, with sides 6 and 4.

The length of a diagonal is:

√(6*6)+(4*4)

√36+16

√52

7.21(rounded off to 3 sig. fig.)

So, 6+4+6+4<2(7.21+7.21)

20< 2*14.42

20<28.84, which is true.

:)

Answer Link

Otras preguntas

Santana is plotting points on a graph. The ratio of y-value to x-value is 3 to 4 for each point. What will be the x-value of a point with a y-value of 12?
What is the perimeter of the largest triangle
An EVEN number of negative signs results in a:__________________
Why do amphibians live near water? a. to prevent drying out and as a food source b. to prevent drying out and to lay their eggs c. to prevent dring out and t
which version of ip offers users nearly limitless ip addresses
In florida if you have a learners permit you may only drive at what time during the first three months
You decide to buy your first car. However, when you go to the dealership they want you to pay in cash and provide you with no contract. What is the benefit of a
if you didn't have macrophages in your body then,
The mediastinum is located within the the cavity
Most historians point to _____ as the birthplace of modern theater.