Answer:
[tex]5*\sqrt{3} =8.660 \frac{m}{s}[/tex]
Explanation:
The horizontal component of he velocity is found using the trigonometric definition of "cosine" of an angle in a right angle triangle:
[tex]cos(\theta)=\frac{adj}{hyp} \\cos(30)=\frac{x}{10} \\10*cos(30)=x\\10* \frac{\sqrt{3} }{2} =x\\x=5*\sqrt{3} =8.660 \frac{m}{s}[/tex]
