Answer:
1124.8 Volt
Explanation:
N = 200, Diameter = 0.18 m, Radius, r = 0.09 m, f = 3250 rpm = 54.17 rps
B = 0.65 T
the peak value of induced emf is given by
e0 = N x B x A x ω
e0 = 200 x 0.65 x 3.14 x 0.09 x 0.09 x 2 x 3.14 x 54.17
e0 = 1124.8 Volt
