Answer:
[tex]\large\boxed{6.\ x=-\dfrac{12}{7}}\\\boxed{7.\ p=0}[/tex]
Step-by-step explanation:
[tex]6.\\\\1-7x+4=18\\(1+4)-7x=18\\5-7x=18\qquad\text{subtract 5 from both sides}\\-7x=12\qquad\text{divide both sides by (-7)}\\x=-\dfrac{12}{7}\\\\7.\\\\5p+10=10\qquad\text{subtract 10 from both sides}\\5p=0\qquad\text{divide both sides by 5}\\p=0[/tex]
