Respuesta :

gmany

Answer:

[tex]\large\boxed{_7P_2=42}[/tex]

Step-by-step explanation:

[tex]_nP_k=\dfrac{n!}{(n-k)!};\ n!=1\cdot2\cdot3\cdot...\cdot n\\\\\text{We have:}\\\\_7P_2=\dfrac{7!}{(7-2)!}=\dfrac{7!}{5!}=\dfrac{5!\cdot6\cdot7}{5!}=6\cdot7=42[/tex]

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