Answer:
[tex]\large\boxed{A\approx213.71\ ft^2}[/tex]
Step-by-step explanation:
Use the formula:
[tex]A=\dfrac{1}{2}bc\sin A[/tex]
We have:
[tex]b=31\ ft,\ c=18\ ft,\ m\angle A=50^o\to\sin50^o\approx0.766[/tex]
Substitute:
[tex]A=\dfrac{1}{2}(31)(18)(0.766)\approx213.71\ ft^2[/tex]
