Answer:
[tex]f^{-1}[/tex](x) = [tex]\frac{4-x}{8}[/tex]
Step-by-step explanation:
let y = - 8x + 4
rearrange making x the subject
add 8x to both sides
8x + y = 4 ( subtract y from both sides )
8x = 4 - y ( divide both sides by 8 )
x = [tex]\frac{4-y}{8}[/tex]
change y back into terms of x, then
[tex]f^{-1}[/tex](x) = [tex]\frac{4-x}{8}[/tex]
