Given- m= 1.75 g
Now moles of O2 gas= Mass/ Molar mass
n = 1.75/32
V= 2L
P= 1atm
R=0.0821.....Constant
As PV=nRT
=> T=PV/nR
= 1* 2/ (1.75/32)*0.0821 K
= 2*32/1.75* 0.0821 K
= 445.45 K
= (445.45- 273.15) degrees celsius
= 172.30 degrees celsius..... ANSWER
