Respuesta :

In step 3, you added 8x onto the other side instead of subtracting it from 15x.

[tex]\bf \begin{array}{rllll} 3(5x-4)&=&8x+2\\\\ 15x-12&=&8x+2\\\\ 7x-12&=&2&\leftarrow \textit{notice here}\\\\ 7x&=&14\\[1em] x&=&\cfrac{14}{7}\\[1em] x&=&2 \end{array}[/tex]

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