Respuesta :

gmany

[tex]The\ zeros:\\\\x=1,\ x=7,\ x=-4\\\downarrow\\x-1=0,\ x-7=0,\ x+4=0\\\downarrow\\w(x)=(x-1)(x-7)(x+4)=(x^2-7x-1x+7)(x+4)\\\\=(x^2-8x+7)(x+4)=x^3+4x^2-8x^2-32x+7x+28\\\\Answer:\ w(x)=x^3-4x^2-25x+28[/tex]